The fractional volume increase of a liquid given CE and ΔT is CE * ΔT. If ΔT = 15°F and CE = 0.000345, what is the fractional change?

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Multiple Choice

The fractional volume increase of a liquid given CE and ΔT is CE * ΔT. If ΔT = 15°F and CE = 0.000345, what is the fractional change?

Think of the fractional volume change as the product of the expansion coefficient and the temperature rise. The coefficient of volumetric expansion tells you how much volume changes per degree of temperature increase, so you multiply by how many degrees you’ve heated.

Here, CE = 0.000345 per °F and ΔT = 15 °F. Multiply: 0.000345 × 15 = 0.005175. This is a dimensionless fraction, which is about 0.5175% (0.005175 × 100).

The fractional volume increase of a liquid given CE and ΔT is CE * ΔT. If ΔT = 15°F and CE = 0.000345, what is the fractional change?

Study for the Washington DC 1st Class Boiler Test. Prepare with comprehensive questions, each with explanations and insights. Equip yourself thoroughly for success!

The fractional volume increase of a liquid given CE and ΔT is CE * ΔT. If ΔT = 15°F and CE = 0.000345, what is the fractional change?

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