For a stay with a diameter of 2.75 inches, what is its approximate cross-sectional area in square inches?

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Multiple Choice

For a stay with a diameter of 2.75 inches, what is its approximate cross-sectional area in square inches?

Explanation:
The area of a circle comes from A = πr^2, or equivalently A = (πτ^2)/4 when using diameter. With a diameter of 2.75 inches, the radius is 1.375 inches, and 1.375^2 = 1.890625. Multiply by π to get A ≈ 3.14159 × 1.890625 ≈ 5.93 square inches. Using A = (πd^2)/4 with d = 2.75 gives the same result: 2.75^2 = 7.5625, times π/4 ≈ 0.7854 yields about 5.93. So the cross-sectional area is approximately 5.93 square inches. The other options would depart from this value when calculated, so they don’t match the correct result.

The area of a circle comes from A = πr^2, or equivalently A = (πτ^2)/4 when using diameter. With a diameter of 2.75 inches, the radius is 1.375 inches, and 1.375^2 = 1.890625. Multiply by π to get A ≈ 3.14159 × 1.890625 ≈ 5.93 square inches. Using A = (πd^2)/4 with d = 2.75 gives the same result: 2.75^2 = 7.5625, times π/4 ≈ 0.7854 yields about 5.93. So the cross-sectional area is approximately 5.93 square inches. The other options would depart from this value when calculated, so they don’t match the correct result.

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